有懂SQL语句的帮金光整个法子

聶十八

哦用了count(*)
' d. e2 z/ ]( S; }5 ]' T没用group by

haney

文盲飘过

ftw

这个很难清出来吧？

三叶草

试试我QQ群里发的，

金光

select author, count(*) from pre_forum_post_2 as b where b.fid='105' and b.tid='863265' and first=0 and mod(( select count(*) as dd from pre_forum_post_2 as a where a.fid='105' and a.tid='863265' and a.pid<b.pid order by pid) ,25)=0 group by author
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select ( select count(*) as dd from pre_forum_post_2 as a where  a.fid='105' and a.tid='863265' and a.pid<b.pid order by pid) as xuhao, author  from pre_forum_post_2 as b where b.fid='105' and b.tid='863265' and first=0 and mod(( select count(*) as dd from pre_forum_post_2 as a where  a.fid='105' and a.tid='863265' and a.pid<b.pid order by pid) ,25)=0
这个是显示发帖的楼层数
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